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First, you would have to balance the reaction, leading to 3I- arrow I3-. Now, there is a -3 charge on the on the left side and -1 charge on the right side. Then, you would add 2 electrons to the right side so the charges on both side would be -3, leading to this being an oxidation reaction.
To find whether it is oxidation or reduction you need to have another reaction to compare it to. Then you would look up both of those reactions in the chart with all the half reactions. Whichever has a more negative value that should be the oxidation, and the more positive value should be reduction.
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