6L.5 part c (7th edition)

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6L.5 part c (7th edition)

Postby 005199302 » Fri Feb 22, 2019 2:38 pm

Write the half-reactions, the balanced equation, and the cell diagram for:
Cl2(g) +H2(g) --> HCl (aq)

So the cathode reaction is: Cl2 + 2e- --> 2Cl-
And the anode reaction (after reversal) is: H2 --> 2H+ + 2e-

In the answer, Cl-(aq) comes before Cl2 (g), and I am wondering why that is the case.

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Re: 6L.5 part c (7th edition)

Postby Chem_Mod » Mon Feb 25, 2019 2:20 pm

This is a typo. The reactant is Cl2(g) and the product is Cl, so the Cl2(g) should be written first.

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