Question 14.19 (Sixth Edition)

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Steve Magana 2I
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Joined: Fri Sep 28, 2018 12:24 am

Question 14.19 (Sixth Edition)

Postby Steve Magana 2I » Mon Feb 25, 2019 1:23 am

Question: A student was given a standard Cu(s) 0 Cu2+(aq) half-cell and another half-cell containing an unknown metal M immersed in 1.00 m M(NO3)2(aq). When the copper was connected as the anode at 25 degrees Celsius, the cell potential was found to be -0.689 V. What is the reduction potential for the unknown M2+/M couple?

I'm having trouble with this problem, can someone help me please? Thank you!

Tam To 1B
Posts: 72
Joined: Fri Sep 28, 2018 12:25 am

Re: Question 14.19 (Sixth Edition)

Postby Tam To 1B » Mon Feb 25, 2019 10:22 am

We know that Cu/Cu2+ is the anode. The standard potential for Cu/Cu2+ which can be found in the Appendix, is +0.34.
You plug this into the E(cell) = E(cathode) - E(anode) equation to find the potential for the cathode, M2+/M.
E(cathode) = E(cell) + E(anode) = -0.689 + 0.34 = -0.349 V.

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