6M5 part a

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Rachel Yoo 1F
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Joined: Fri Sep 28, 2018 12:24 am

6M5 part a

Postby Rachel Yoo 1F » Mon Feb 25, 2019 4:40 pm

For the cell diagram the answer doesn't include a platinum(s) on the anode side when there is no solid. It only has Hg(l) and Hg2 2+(aq). I thought we had to always include Pt(s) when there's no solid so why does the answer not include it on this side?

Camille Marangi 2E
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

Re: 6M5 part a

Postby Camille Marangi 2E » Mon Feb 25, 2019 8:29 pm

Mercury acts as a conductor when it is in a liquid state, so there is no need for an additional conducting metal.

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Re: 6M5 part a

Postby paytonm1H » Tue Feb 26, 2019 10:35 pm

how do you know what liquids are conducting??

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