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6M5 part a

Posted: Mon Feb 25, 2019 4:40 pm
by Rachel Yoo 1F
For the cell diagram the answer doesn't include a platinum(s) on the anode side when there is no solid. It only has Hg(l) and Hg2 2+(aq). I thought we had to always include Pt(s) when there's no solid so why does the answer not include it on this side?

Re: 6M5 part a

Posted: Mon Feb 25, 2019 8:29 pm
by Camille Marangi 2E
Mercury acts as a conductor when it is in a liquid state, so there is no need for an additional conducting metal.

Re: 6M5 part a

Posted: Tue Feb 26, 2019 10:35 pm
by paytonm1H
how do you know what liquids are conducting??