6th edition 14.31

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katherinemurk 2B
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6th edition 14.31

Postby katherinemurk 2B » Mon Feb 25, 2019 6:03 pm

In the solutions manual for part d it says NO3- is the oxidizing agent and it is in the cathode, but how is this possible if it goes from NO3- to No2. Is it not losing an electron, therefore it is oxidizing so it is part of the anode??

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Re: 6th edition 14.31

Postby Chem_Mod » Wed Feb 27, 2019 7:26 pm

It is the oxidizing agent because it is being reduced. This is an easy thing to confuse. Just remember that when something is an agent, it is talking about what effect that compound has on another compound. In this case, nitrate takes electrons to become nitrate, and is being reduced, therefore it must oxidize something else.


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