Cell Diagrams Example 14.4 in 6th Edition Book

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taywebb
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Cell Diagrams Example 14.4 in 6th Edition Book

Postby taywebb » Mon Feb 25, 2019 8:23 pm

Can anyone explain to me how they came up with the reduction and oxidation half-reactions for the cell diagram Pt(s)|H2(g)|HCl(aq)|Hg2Cl2(aq)|Hg(l)? I am confused at how they got Cl- as a separate component when it is not in the cell diagram and why the coefficient for H2(g) becomes 1/2 in the oxidation half-reaction.
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Miya Lopez 1I
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Re: Cell Diagrams Example 14.4 in 6th Edition Book

Postby Miya Lopez 1I » Mon Feb 25, 2019 8:44 pm

I'm confused about this diagram as well, but maybe it is just assumed Cl- will be a separate component?

Miya Lopez 1I
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Joined: Tue Nov 14, 2017 3:00 am
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Re: Cell Diagrams Example 14.4 in 6th Edition Book

Postby Miya Lopez 1I » Mon Feb 25, 2019 8:48 pm

Pt(s) | H2(g) | HCl(aq) | Hg2Cl2(s) | Hg(l)

From Step 1:
Cl-|Hg2Cl2|Hg
From Step 2:
Pt|H2|H+

To me, it looks like they divide the cell Pt(s) | H2(g) | HCl(aq) | Hg2Cl2(s) | Hg(l) in the middle and separate HCl into H+ and Cl-


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