half reactions for problem 6L.5 c 7th edition

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Cecilia Jardon 1I
Posts: 74
Joined: Fri Sep 28, 2018 12:16 am

half reactions for problem 6L.5 c 7th edition

Postby Cecilia Jardon 1I » Mon Feb 25, 2019 10:32 pm

It says to write the half-reaction for Cl2(g) +H2(g)--> HCL (aq)
i thought that it would be for the
reduction: 2H+ (aq) + Cl2(g) + 2e- --> HCl(aq)
but on the solution manual it says that the answer is Cl2(g) + 2e- --> 2Cl-
Why is that? Can someone explain this please.

Andrew Bennecke
Posts: 62
Joined: Fri Sep 28, 2018 12:15 am

Re: half reactions for problem 6L.5 c 7th edition

Postby Andrew Bennecke » Tue Feb 26, 2019 8:59 am

You have to split up the product, HCl, into its ions, H+ and Cl-. When you do this, the reduction half reaction is Cl2(g) + 2e- ->2Cl- and the oxidation half reaction is H2(g) -> 2H+(aq) + 2e-.


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