How do we know to add Pt(s) to the cell diagram?
example: 14.13 Write the half-reactions, the balanced equation for the cell reaction, and the cell diagram for each of the following skeletal equations:
(b) Ce4+(aq) + I-(aq) --> I2(s) + Ce3+(aq)
Pt(s) in cell diagram
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Re: Pt(s) in cell diagram
You would add Pt to the Ce4+ side of the diagram as it has no solids to conduct the charges. We use Pt when there are no solids in the half reaction.
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Re: Pt(s) in cell diagram
the metal conductor is always added to the outer part of the cell diagram.
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Re: Pt(s) in cell diagram
Shubham Rai 2C wrote:You would add Pt to the Ce4+ side of the diagram as it has no solids to conduct the charges. We use Pt when there are no solids in the half reaction.
the solutions show Pt(s) on both sides of the cell diagram though
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Re: Pt(s) in cell diagram
I was confused about that too, but I came to the conclusion that since iodine is not actually a metal then iodine in solid form would not really be fit to be a conductor.
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