7th Edition, 6L.7a

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Andrew Bennecke
Posts: 62
Joined: Fri Sep 28, 2018 12:15 am

7th Edition, 6L.7a

Postby Andrew Bennecke » Tue Feb 26, 2019 9:05 am

Write the half reactions and devise a galvanic cell (write a cell diagram) to study the following reaction:
AgBr(s) -> Ag+(aq) + Br-(aq)
Could someone please explain to me why, in the answer key, they have the oxidation half reaction as Ag(s) + Br-(aq) -> AgBr (s) + 1e- and the reduction half reaction as Ag+(aq) + Br(s) +1e- -> AgBr (s)?

Andrew Bennecke
Posts: 62
Joined: Fri Sep 28, 2018 12:15 am

Re: 7th Edition, 6L.7a

Postby Andrew Bennecke » Tue Feb 26, 2019 9:08 am

The correct reduction half reaction is actually Ag+(aq) + 1e- -> Ag(s) in the book.


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