Page 1 of 1

#14.13 Part C (Sixth Edition)

Posted: Tue Feb 26, 2019 1:48 pm
by gabbym
Can someone help me with #14.13 Part C? It asks you to write the half-reactions, the balanced equation for the cell reaction, and the cell diagram for each of the following
skeletal equations:
(c) Cl2(g) / H2(g) --> HCl(aq)
I don't understand how they are getting the half reactions. Can someone explain it to me?

Re: #14.13 Part C (Sixth Edition)

Posted: Tue Feb 26, 2019 4:13 pm
by Lynsea_Southwick_2K
I did one half rxn in regards to the Cl2(g) and then the other in regards to H2(g), then when you combine the half rxns you get 2H+(aq) and 2Cl-(aq) on the product side which is also 2HCl

Re: #14.13 Part C (Sixth Edition)

Posted: Wed Feb 27, 2019 2:14 pm
by gabbym
But I'm not understanding how you arrive at that conclusion for the half reactions. How do you know to separate the HCl into Cl- and H+? I would have just put that Cl2 goes to HCl and then H2 goes to HCl

Re: #14.13 Part C (Sixth Edition)

Posted: Sat Mar 09, 2019 10:02 pm
by annabel 2A
I think that you're supposed to assume that HCl dissociates into its ions in an aqueous solution because it is a strong acid, so you're supposed to see the equation as Cl2(g) + H2(g) --> 2H+(aq) + 2Cl-(aq)