6M.13 in 7th edition

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005199302
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6M.13 in 7th edition

Postby 005199302 » Tue Feb 26, 2019 2:28 pm

in part d, the reduction equation is: O3(g)+H20(l)+2e- --> O2(g)+2OH-

Why does OH-(aq) come before O3(g),O2(g) in the cell diagram, when it is a product of the half reaction?

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Re: 6M.13 in 7th edition

Postby Chem_Mod » Wed Feb 27, 2019 7:18 pm

For the cathode side of the cell diagram, aqueous compounds are written before gaseous compounds. I am unclear about what you are asking in the second part of your question.


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