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14.23, part a

Posted: Wed Feb 27, 2019 11:28 pm
by Steven Garcia 1H
According to the solution manual, the cell diagram is shown without a solid conductor on the left hand side (anode side). I was curious as to why this is or if this was an error. The elements on the anode side of the cell diagram consist of the liquid Hg(l) and the aqueous solution Hg22+

Re: 14.23, part a

Posted: Sat Mar 02, 2019 5:56 am
by Chem_Mod
liquid mercury is a conductor so itself can conduct electron and no need to add another solid electrode

Re: 14.23, part a

Posted: Sat Mar 02, 2019 11:42 am
by Lopez_Melissa-Dis4E
Mercury is an electron conductor itself, therefore it does not need a solid like Pt(s) written in the cell diagram.