6M. 1 7th Edition

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Daniel Lai
Posts: 65
Joined: Fri Sep 28, 2018 12:28 am

6M. 1 7th Edition

Postby Daniel Lai » Sat Mar 09, 2019 3:24 pm

A student was given a standard Cu(s)|Cu2+(aq) half-cell and another half-cell containing an unknown metal M in 1.00 M M(NO3)2 (aq) and formed the cell M(s)|M+||Cu2+(aq)|Cu(s). The cell potential was found to be -0.689 V. What is the value of E(M2+/M)?

I don't understand how we're supposed to know which one is the anode or cathode. I did the question with the M side as the anode and the Cu side as the cathode but the answer is incorrect. The solution manual does it with Cu as the anode and M as the cathode. Can anyone explain why?

Kristen Kim 2K
Posts: 70
Joined: Fri Sep 28, 2018 12:16 am

Re: 6M. 1 7th Edition

Postby Kristen Kim 2K » Sat Mar 09, 2019 3:39 pm

The cell diagram is structured so that it indicates the anode is on the left of the salt bridge (||) and the cathode is on the right side.

Cole Doolittle 2K
Posts: 30
Joined: Fri Sep 28, 2018 12:20 am

Re: 6M. 1 7th Edition

Postby Cole Doolittle 2K » Sat Mar 09, 2019 4:50 pm

This sounds like the question is just trying to be tricky. We were taught to write anode on the left and cathode on the right.


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