Test 2 #6 part c

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Rachel Yoo 1F
Posts: 65
Joined: Fri Sep 28, 2018 12:24 am

Test 2 #6 part c

Postby Rachel Yoo 1F » Wed Mar 13, 2019 1:04 am

Did anyone get #6 part c right and if you did could you give me the answer and how you got it because I got a and b right but c wrong and I'm not sure what I did wrong

David Effio 1H
Posts: 38
Joined: Wed Feb 14, 2018 3:01 am

Re: Test 2 #6 part c

Postby David Effio 1H » Wed Mar 13, 2019 1:26 am

I believe that everyone gets different numbers, but I'll try to explain based on my numbers.

In order to get the correct answer, you need to choose the species with the strongest reducing power and strongest oxidation power. In my case, Sn had the highest reducing power and an E of -0.14 V. Pb2+ had the highest oxidation power, with E of -0.13.

In that case, we use the one with the strongest reducing power as the anode and the strongest oxidizing power as the cathode.

Therefore Ecell = -0.13 - -0.14 = 0.01 V, which resulted in the greatest

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