Test 2 #6 part c

[Rachel Yoo 1F]

Did anyone get #6 part c right and if you did could you give me the answer and how you got it because I got a and b right but c wrong and I'm not sure what I did wrong

[David Effio 1H]

I believe that everyone gets different numbers, but I'll try to explain based on my numbers.

In order to get the correct answer, you need to choose the species with the strongest reducing power and strongest oxidation power. In my case, Sn had the highest reducing power and an E of -0.14 V. Pb2+ had the highest oxidation power, with E of -0.13.

In that case, we use the one with the strongest reducing power as the anode and the strongest oxidizing power as the cathode.

Therefore Ecell = -0.13 - -0.14 = 0.01 V, which resulted in the greatest