## 7th Edition 6N.9

Gillian Ward 1F
Posts: 61
Joined: Fri Sep 28, 2018 12:27 am

### 7th Edition 6N.9

A tin electrode in 0.015M Sn(NO3)2(aq) is connected to a hydrogen electrode in which the pressure of H2 is 1.0 bar. If the cell potential is 0.061 V at 25 degrees Celsius, what is the pH of the electrolyte at the hydrogen electrode?

How do you set up the cell equation with the given information? I'm confused as to how they were able to get the products and reactants.

keyaluo4C
Posts: 54
Joined: Fri Sep 28, 2018 12:17 am

### Re: 7th Edition 6N.9

To find the pH you need to first find [H+].
To find the concentration of H+ use the equation:
$E_{cell}=E_{cell}^{\circ}-\frac{0.0592 V}{n}\textup{logQ}$
Q in the equation is equal to $\frac{[Sn^{2+}]}{[H^{+}]^{2}}$
You would then solve for the concentration of H+ and then calculate pH.