Platinum in cell diagrams

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Casey Collet 1I
Posts: 23
Joined: Fri Sep 26, 2014 2:02 pm

Platinum in cell diagrams

Postby Casey Collet 1I » Mon Feb 09, 2015 5:05 pm

I keep getting confused on the conditions in which you use Platinum as an inert conductor in cell diagrams. If a metal is present, but is liquid instead of solid, can that metal still act as the electrode? Is it only with gases and nonmetals that platinum must be present?

Regina Chi 2K
Posts: 51
Joined: Fri Sep 26, 2014 2:02 pm

Re: Platinum in cell diagrams

Postby Regina Chi 2K » Mon Feb 09, 2015 6:40 pm

You must have a solid present. If both species are either gases, liquids, or aqueous solutions, you must add an electrode.

Casey Collet 1I
Posts: 23
Joined: Fri Sep 26, 2014 2:02 pm

Re: Platinum in cell diagrams

Postby Casey Collet 1I » Mon Feb 09, 2015 6:45 pm

Okay that's what I thought, but then why on problem 13.21 part a does the cell diagram for the anode look like Hg(l) l Hg2^(2+) (aq), where there isn't a solid present, but it indicates that mercury is acting as the electrode?

Justin Le 2I
Posts: 142
Joined: Fri Sep 26, 2014 2:02 pm

Re: Platinum in cell diagrams

Postby Justin Le 2I » Tue Feb 10, 2015 12:23 am

I think Hg (l) is an exception and can be an electrode because I see it being used as one in 19c and 43a.

Eva Guillory 2E
Posts: 44
Joined: Fri Sep 28, 2018 12:22 am

Re: Platinum in cell diagrams

Postby Eva Guillory 2E » Tue Feb 26, 2019 4:37 pm

This makes sense, but I'm confused, because for the answer of 6L.5 part b in the 7th edition (which i listed below), despite Iodine being a solid, platinum is still included? In the solution manual, it does say that "An inert electrode such as Pt is necessary when both oxidized and reduced species are in the same solution," but how would we know that they are in the same solution?

Pt(s)|I-(aq)|I2 (s) || Ce4+ (aq), Ce3- (aq) | Pt(s)


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