6L.7

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Ryan Chang 1C
Posts: 105
Joined: Sat Aug 24, 2019 12:17 am

6L.7

Postby Ryan Chang 1C » Fri Feb 21, 2020 5:40 pm

Write the half-reactions and devise a galvanic cell (write a cell diagram) to study each of the following reactions:
(a) AgBr(s) -> Ag+(aq) + Br-(aq), a solubility equilibrium

In the half reaction for the anode, the answer key gives the following reaction: AgBr(s) + e- -> Ag(s) + Br-(aq)
Why doesn't Ag(s) have a positive charge?

AArmellini_1I
Posts: 107
Joined: Fri Aug 09, 2019 12:15 am

Re: 6L.7

Postby AArmellini_1I » Sat Feb 22, 2020 5:52 pm

Ag(s) doesn't have a positive charge because it is not interacting with another element and therefore cannot be gaining or losing an electron


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