Standard Cell Potentials

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Cole Woulbroun 1J
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Joined: Thu Jul 25, 2019 12:16 am

Standard Cell Potentials

Postby Cole Woulbroun 1J » Sat Feb 22, 2020 5:36 pm

When standard cell potentials are used, they are calculated with the reduction potentials of the cathode an anode half reactions with the equation E(cell) = E(cathode) - E(anode), correct? Did anyone else see a different, possibly incorrect answer on the solutions manual for question 6M.1?

Elena Bell 1C
Posts: 64
Joined: Thu Jul 11, 2019 12:16 am

Re: Standard Cell Potentials

Postby Elena Bell 1C » Sat Feb 22, 2020 5:45 pm

My solutions manual has the copper anode and its potential is 0.34 V. The cell potential is given as -0.689 V. You would set up an equation for -0.689 V= E not of the cathode - 0.34 V. Then, solve for E not of the cathode and you should get -0.349 V.

Haley Dveirin 1E
Posts: 101
Joined: Sat Jul 20, 2019 12:17 am

Re: Standard Cell Potentials

Postby Haley Dveirin 1E » Sat Feb 22, 2020 6:23 pm

Yeah so E^o(cell) is given to be -0.689V. In the table 6M1 E^o of the anode half reaction Cu2+ + 2e- -> Cu is given as +0.34. So the equation would be:
E^o(cell)=E^o(cathode)-E^o(anode) which is -0.689=E^o(cathode)+0.34. Then you solve for E^o(cathode)

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