Platinum Cell Diagram

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Alex Tchekanov Dis 2k
Posts: 118
Joined: Sat Aug 24, 2019 12:16 am

Platinum Cell Diagram

Postby Alex Tchekanov Dis 2k » Sun Feb 23, 2020 3:08 pm

For questions 6L5 part b: Ce4+(aq) + I-(aq) = I2(s) + Ce3+(aq)
The answer for the cell diagram has platinum on both sides, why do you put platinum on the left side with the Iodine if there is a solid form of it?

lilymayek_1E
Posts: 107
Joined: Sat Aug 17, 2019 12:16 am

Re: Platinum Cell Diagram

Postby lilymayek_1E » Sun Feb 23, 2020 4:11 pm

platinum is used when there are no conducting solids, and Iodine in a solid form isn't a conductor; if you look on a periodic table, Iodine is one of the noble gases, which are all nonmetals (& on the nonmetal "side" of the table) and generally unreactive. they can't conduct electricity because of their nonmetallic traits.

Robert Tran 1B
Posts: 118
Joined: Thu Jul 11, 2019 12:15 am

Re: Platinum Cell Diagram

Postby Robert Tran 1B » Sun Feb 23, 2020 5:32 pm

Although iodine is a solid, it is not a conductor. Thus, we need to put a conducting metal (platinum) in order for the reaction to occur.


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