Platinum Cell Diagram

[Alex Tchekanov Dis 2k]

For questions 6L5 part b: Ce4+(aq) + I-(aq) = I2(s) + Ce3+(aq)
The answer for the cell diagram has platinum on both sides, why do you put platinum on the left side with the Iodine if there is a solid form of it?

[lilymayek_1E]

platinum is used when there are no conducting solids, and Iodine in a solid form isn't a conductor; if you look on a periodic table, Iodine is one of the noble gases, which are all nonmetals (& on the nonmetal "side" of the table) and generally unreactive. they can't conduct electricity because of their nonmetallic traits.

[Robert Tran 1B]

Although iodine is a solid, it is not a conductor. Thus, we need to put a conducting metal (platinum) in order for the reaction to occur.