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Cell Diagram with one reactant

Posted: Sun Feb 23, 2020 3:11 pm
by Alex Tchekanov Dis 2k
For problem 6L7 part A: AgBr(s) = Ag+(aq) + Br-(aq)
For questions like these when you only have one reactant and it is a solid, how do you know how to break it down in the anode and cathode half-reactions? Is it problem by problem-based or is there a set of rules that you can follow to know how to do this?

Re: Cell Diagram with one reactant

Posted: Sun Feb 23, 2020 5:33 pm
by Daniela Shatzki 2E
I think it depends on when you break the equations down, is there a clear one that has something being reduced and a clear one that has something being oxidized. Then you can decide which is the anode and which is the cathode.