6L.1

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Brittney Hun 2C
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Joined: Wed Sep 11, 2019 12:15 am

6L.1

Postby Brittney Hun 2C » Tue Feb 25, 2020 2:07 pm

For part b of the problem it shows an already balanced redox reaction. I'm having trouble finding n for it because I don't know exactly how the charges for hydrogen and water would work.
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MAC 4G
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Joined: Wed Sep 18, 2019 12:16 am

Re: 6L.1

Postby MAC 4G » Tue Feb 25, 2020 2:48 pm

I think you can look at the redox pair: Fe3+ and Fe2+. Since there are 6 of Fe3+ that means the charge is 18+. There are 6 of Fe2+ so the charge is 12+. The difference between the two is 6 electrons.
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Skyllar Kuppinger 1F
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Joined: Thu Jul 25, 2019 12:16 am

Re: 6L.1

Postby Skyllar Kuppinger 1F » Tue Feb 25, 2020 5:10 pm

MAC 4G wrote:I think you can look at the redox pair: Fe3+ and Fe2+. Since there are 6 of Fe3+ that means the charge is 18+. There are 6 of Fe2+ so the charge is 12+. The difference between the two is 6 electrons.


How come the the Cr pair doesn't work then? 2 of Cr3+ = 6+, but then you have Cr2O72- so you're going from 6+ to 2- That is not a difference of 6. Why doesn't it match the Fe pair?
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