Moderators: Chem_Mod, Chem_Admin

Posts: 111
Joined: Fri Aug 09, 2019 12:16 am


Postby claudia_1h » Tue Feb 25, 2020 4:26 pm

For 6L.3b, we are given the following cell diagram:

C(gr) | H2(g) | H+(aq) || Cl- (aq) | Cl2 (g) | Pt (s)

Can someone explain what the C(gr) part is and how we are supposed to use it when writing the half reactions?

Skyllar Kuppinger 1F
Posts: 52
Joined: Thu Jul 25, 2019 12:16 am

Re: 6L.3b

Postby Skyllar Kuppinger 1F » Tue Feb 25, 2020 5:27 pm

I think the C(gr) means graphite and it is being used as an electrode

Jessa Maheras 4F
Posts: 121
Joined: Fri Aug 02, 2019 12:16 am

Re: 6L.3b

Postby Jessa Maheras 4F » Tue Feb 25, 2020 7:59 pm

The C should be a graphite electrode! You can tell this because it is on the far end of the cell diagram.

Posts: 101
Joined: Sat Sep 07, 2019 12:16 am

Re: 6L.3b

Postby EvanWang » Tue Feb 25, 2020 8:08 pm

C(gr) is used as an electrode because the anode has Hydrogen gas and hydrogen aqueous, so a solid must be included to allow electron transfer. Graphite and Platinum are common inert solids used as electrodes.

Return to “Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams”

Who is online

Users browsing this forum: No registered users and 2 guests