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Postby Shanzey » Wed Feb 26, 2020 11:53 am

For part 6L.5d, the solutions manual splits two half reactions while including Au(s) in both half reactions. Why do we need to have a solid in each half reaction? Can we not have half reactions with just aqueous substances, thus causing us to have the solids in both half reactions?

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Re: 6L.5

Postby 705302428 » Wed Feb 26, 2020 12:37 pm

Because you need the solid as a cathode/anode to transfer the electrons.

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Re: 6L.5

Postby Veronica_Lubera_2A » Wed Feb 26, 2020 3:36 pm

When you write the half reactions, you need to have the solid in the equation because it is in its most stable form (gain of electrons to eliminate the +1 and +3 charge in Au). When we are writing the cell notation, we still need to include the solid since it is in our half reactions with a bar separation since there is a change in state (solid vs. aqueous).

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