6L5D

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705121606
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Joined: Wed Sep 18, 2019 12:17 am

6L5D

Postby 705121606 » Wed Feb 26, 2020 8:51 pm

Can someone explain how we write the cell diagrams for this problem? I thought Au+ would be on both the anode and cathode side because each half reaction has that, instead they have Au(s) on both sides

Vincent Leong 2B
Posts: 207
Joined: Fri Aug 09, 2019 12:15 am

Re: 6L5D

Postby Vincent Leong 2B » Thu Feb 27, 2020 1:17 am

I think the key to this question is knowing that there has to be a metal electrode to conduct the electrons current through the metal wire of the cell. I think it's also a huge indicator that we're considering the Au(s) on both sides because the overall reaction is missing one reactant which is not typical when combining two half redox rxns. Usually, the overall rxn looks like A + B --> C + D. Because only Au+ is the only reactant, that must mean Au(s) or a reactant when reducing or oxidizing Au+ is cancelled out when balancing half rxns


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