6l7

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705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

6l7

Postby 705121606 » Sat Feb 29, 2020 6:12 pm

When we make a cell diagram for cd(s) + 2Ni(OH)3 (s) --> Cd(OH)2 (s) + 2Ni(OH)s (s) at first I was confused on why the cell diagram would look like Cd|Cd(OH)2|KOH||Ni(OH)3|Ni(OH)2|Ni

because I didn't know why we added the KOH but I was informed we needed it because since when we were balancing, we added OH to the equation. But I am still confused because how come we don't have to add an OH for the nickel side of the cell diagram?

Elena Bell 1C
Posts: 64
Joined: Thu Jul 11, 2019 12:16 am

Re: 6l7

Postby Elena Bell 1C » Sat Feb 29, 2020 6:16 pm

The nickel is being reduced, so the Ni(OH)3 already has OH that is given off, and there is no additional OH added. The cadmium is oxidized and you have to add OH to the solid Cd in order to get Cd(OH)2.


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