6L. 5 c)

Moderators: Chem_Mod, Chem_Admin

Labiba Sardar 2A
Posts: 103
Joined: Sat Jul 20, 2019 12:15 am

6L. 5 c)

Postby Labiba Sardar 2A » Sat Feb 29, 2020 6:45 pm

For the given reaction, Cl2 (g) + H2 (g) --> HCl (aq), when writing the half reactions, why is the product 2Cl- for the reduction of Cl2 and the product for the oxidation of H2 is 2H+? Why aren't the products HCl like how it's given in the question?

Tyler Angtuaco 1G
Posts: 130
Joined: Wed Sep 11, 2019 12:16 am

Re: 6L. 5 c)

Postby Tyler Angtuaco 1G » Sat Feb 29, 2020 6:55 pm

Since HCl is a strong acid and is aqueous, you can imagine most if not all of the ions in the solution to be present as H+ and Cl- ions. Thus, you are analyzing the reduction of Cl2 to these Cl- ions and the oxidation of H2 into these H+ ions.

Return to “Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams”

Who is online

Users browsing this forum: No registered users and 2 guests