6L #7c

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6L #7c

Postby LBacker_2E » Sat Feb 29, 2020 7:10 pm

I am very confused how the book got a cell diagram that contained KOH as the aqueous compound on the anode side instead of just OH-. Also why is there Ni(s) on the cathode side and no OH- present?

Sue Bin Park 2I
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Re: 6L #7c

Postby Sue Bin Park 2I » Sun Mar 01, 2020 2:17 pm

i'd guess KOH is used because it is a completely soluble salt of OH- that does not interact with the desired reaction in any way. it probably could have also been NaOH? i don't really understand why we can't just write OH- like we did in 6L.7b but maybe someone else can chime in on that...

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