6L #7c
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LBacker_2E
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6L #7c
I am very confused how the book got a cell diagram that contained KOH as the aqueous compound on the anode side instead of just OH-. Also why is there Ni(s) on the cathode side and no OH- present?
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Sue Bin Park 2I
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Re: 6L #7c
i'd guess KOH is used because it is a completely soluble salt of OH- that does not interact with the desired reaction in any way. it probably could have also been NaOH? i don't really understand why we can't just write OH- like we did in 6L.7b but maybe someone else can chime in on that...
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