6M.1: reading the cell diagram

[Edmund Zhi 2B]

In this question, we are given M(s)|M2+(aq)||Cu^2+(aq)|Cu(s) as the cell diagram and are asked to find E(M2+/M) given E(cell) = -0.689.
Now normally, we would consider the right side to be the cathode, right? So in that case, we setup the equation to as
E(cell) = E(cathode) - E(anode)
-0.689 = 0.337 - E(anode)
E(anode) = 1.026

However, the answer key gives us a value of -0.349. To get this, we would have to consider copper as the ANODE. Why is this?

[Alex Chen 2L]

I'm going to agree with you and say that the book made a mistake. Seems like they accidentally flipped the sign for E cell during calculations, from what I've seen in the solution manual.

[Alice Chang 2H]

I had a TON of trouble with this one too!

I eventually gave up and assumed the textbook made a mistake and flipped the entire cell diagram around. Or, we were supposed to flip the cell diagram ourselves (?) since we were asked for E(M2+/M) rather than E(M/M2+).

[705121606]

I also had trouble with this one, I read on another chemistry community question that when the ecell is negative we have to flip the cell around

[Edmund Zhi 2B]

I also had trouble with this one, I read on another chemistry community question that when the ecell is negative we have to flip the cell around

Update: I looked at the solutions manual and they did consider the cell to be flipped. Guess the textbook is wrong

[Rodrigo2J]

I got the same answer you did, I think the solutions had an error.

[Rida Ismail 2E]

I got the same answer as you. I am going to try to go to an office hour to ask this question, but my guess is that the book is wrong.