6M.13

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Letty Liu 2C
Posts: 105
Joined: Fri Aug 09, 2019 12:16 am

6M.13

Postby Letty Liu 2C » Sun Mar 01, 2020 1:38 pm

Identify the reactions with K . 1 in the following list and, for each such reaction, identify the oxidizing agent and calculate
standard cell potential. For part b, shouldn't the SRP for Ce3+ -> Ce 4+ be -1.61 since it's the reversed reaction of Ce4+ -> Ce3+?

Do we just ignore the equation we're given and base it off of how the reduction half-reaction in the appendix is written?

505316964
Posts: 95
Joined: Thu Jul 11, 2019 12:17 am

Re: 6M.13

Postby 505316964 » Sun Mar 01, 2020 2:26 pm

Even though your reaction may be flipped, you use the E naught value given because E naught is your reaction potential. It's not like Delta H naught where you can use Hesse's Law to change the signs or multiply. If you manipulate the equation the E naught stays the same.

Alex Tchekanov Dis 2k
Posts: 118
Joined: Sat Aug 24, 2019 12:16 am

Re: 6M.13

Postby Alex Tchekanov Dis 2k » Sun Mar 01, 2020 2:30 pm

You don't change the sign of the potential because when you use the equation E = right - left, the signs get switched for you


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