Electrolysis (6.O.1)

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EthanPham_1G
Posts: 104
Joined: Sat Jul 20, 2019 12:17 am

Electrolysis (6.O.1)

Postby EthanPham_1G » Mon Mar 02, 2020 12:29 am

How are we supposed to find the cathode and anode reactions for the electrolysis of NiSO4? I found the cathode reaction for Ni+2 + 2e- --> Ni. I can't find the anode reaction in the appendix?

peteryim
Posts: 54
Joined: Sat Sep 07, 2019 12:17 am

Re: Electrolysis (6.O.1)

Postby peteryim » Mon Mar 02, 2020 12:31 am

You can always look it up on google.

EthanPham_1G
Posts: 104
Joined: Sat Jul 20, 2019 12:17 am

Re: Electrolysis (6.O.1)

Postby EthanPham_1G » Tue Mar 03, 2020 5:49 pm

So apparently, H20 is what is getting oxidized in the anode instead of SO4? Is this because SO4 is a spectator ion?

Rida Ismail 2E
Posts: 139
Joined: Sat Sep 07, 2019 12:16 am

Re: Electrolysis (6.O.1)

Postby Rida Ismail 2E » Wed Mar 04, 2020 12:30 am

I think the water is always one of the half reactions. It will give you an element and given the ox number you look it up in the back of the book (appendix 2B). Then figure our which is reduced and which is oxidized from the Ecell standard.


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