6L5 b.

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MariaJohn1D
Posts: 50
Joined: Wed Nov 08, 2017 3:01 am

6L5 b.

Postby MariaJohn1D » Mon Mar 02, 2020 2:21 pm

Why do we use platinum on both sides in this case? Because one side already has a solid product?

Brian Tangsombatvisit 1C
Posts: 119
Joined: Sat Aug 17, 2019 12:15 am

Re: 6L5 b.

Postby Brian Tangsombatvisit 1C » Mon Mar 02, 2020 2:41 pm

You need to use platinum as a metal electrode for both sides since none of the products or reactants are conducting metal solids. I2 is a solid at the anode, but since it is a metal it doesn't count. At the cathode, there are only aqueous ions so you would also need the platinum electrode here to allow the flow of electrons from the anode to the cathode.

MariaJohn1D
Posts: 50
Joined: Wed Nov 08, 2017 3:01 am

Re: 6L5 b.

Postby MariaJohn1D » Mon Mar 02, 2020 5:20 pm

Brian Tangsombatvisit 1C wrote:You need to use platinum as a metal electrode for both sides since none of the products or reactants are conducting metal solids. I2 is a solid at the anode, but since it is a metal it doesn't count. At the cathode, there are only aqueous ions so you would also need the platinum electrode here to allow the flow of electrons from the anode to the cathode.

I thought I is a nonmetal?

anjali41
Posts: 109
Joined: Fri Aug 09, 2019 12:15 am

Re: 6L5 b.

Postby anjali41 » Mon Mar 02, 2020 5:44 pm

I think he meant to say nonmetal, as the electrode must be both solid and metal.


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