6L.3D

[Savannah Mance 4G]

Can someone please explain the oxidation rxn with the anode for this one? I'm confused because the anode is O2 and H+ , how would this make up the anode rxn if it's not H20 to H+?

[Charlyn Ghoubrial 2I]

Your half reactions should be
Reduction: O2 + 2H2O + 4e- —> 4OH-
Oxidation: 2H2O —> O2 + 4H+ + 4e-
Cancel out the O2, 4e-
Balanced equation: 4H2O —> 4H+ + 4OH- which reduces to H2O —> H+ + OH-

[Savannah Mance 4G]

So, from the cell diagram, the two elements don't have to be on opposite sides of the rxn? Like since O2 and H+ on the anode side of the cell diagram doesn't have to have a half rxn of O2--->H+?

[Angela Wu-2H]

So, from the cell diagram, the two elements don't have to be on opposite sides of the rxn? Like since O2 and H+ on the anode side of the cell diagram doesn't have to have a half rxn of O2--->H+?

I have the same question. Shouldn't the half reaction go from O2 to H+ because the cell diagram says O2(g)|H+(aq)? Where did they randomly get the H2O from and how was I supposed to know to use H2O?