n

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Ruby Richter 2L
Posts: 103
Joined: Thu Jul 25, 2019 12:17 am

n

Postby Ruby Richter 2L » Tue Mar 03, 2020 12:20 pm

how exactly do you determine n or the number of electrons transferred

Rita Chen 1B
Posts: 112
Joined: Sat Jul 20, 2019 12:15 am

Re: n

Postby Rita Chen 1B » Tue Mar 03, 2020 12:46 pm

I think you find the amount of electrons transferred in the balanced reaction. So it is the number of electrons that eventually cancels out.

Minh Ngo 4G
Posts: 137
Joined: Thu Jul 25, 2019 12:17 am

Re: n

Postby Minh Ngo 4G » Tue Mar 03, 2020 12:55 pm

You would determine it from your half reaction (making sure that both of them have the same number of electrons; if not, multiply one with another)

kim 2I
Posts: 105
Joined: Thu Jul 25, 2019 12:17 am

Re: n

Postby kim 2I » Tue Mar 03, 2020 1:50 pm

The number of electrons transferred, n, can be found by looking at the two half-reactions that are combined to formed the overall reaction of the cell. Electrons being lost in the oxidation rxn should be equal to the number of electrons being gained in the reduction rxn. Therefore, if the number of electrons in the half-rxns do not match, make sure to multiply the rxns by a factor that makes them equal to each other (so that they can cancel out).

Hailey Kim 4G
Posts: 110
Joined: Sat Jul 20, 2019 12:16 am

Re: n

Postby Hailey Kim 4G » Tue Mar 03, 2020 1:52 pm

The number of electrons transferred is determined by your half-reactions. n is equal to the same number of electrons needed (in both the oxidation and reduction reactions) to balance out the charge between the reactants and products.


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