6N.9 Homework

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6N.9 Homework

Postby briannam_1F » Tue Mar 03, 2020 1:33 pm

A tin electrode in 0.015 m Sn(NO3)2(aq) is connected to a hydrogen electrode in which the pressure of H2 is 1.0 bar. If the cell potential is 0.061 V at 25 8C, what is the pH of the electrolyte at the hydrogen electrode?

--> When given Sn(NO3)2(aq) how does one know that it is going to be Sn --> Sn2+ 2e- ?
---> When half reactions are found, how one determine which is going to be the anode and which is going to be a cathode?

Ariel Davydov 1C
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Re: 6N.9 Homework

Postby Ariel Davydov 1C » Tue Mar 03, 2020 3:56 pm

1) We know it will be Sn -> Sn2+ + 2e- because the charge of Sn in the salt mentioned is +2.
2) When given the standard reduction potentials of each half reaction for a spontaneous reaction, we know that the half reaction with the highest reduction potential will be reduced and thus will be at the cathode. The half reaction with the lower reduction potential will be oxidized and thus will be at the anode. Hope this helps!

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