6M.5 Part b

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6M.5 Part b

Postby aphung1E » Tue Mar 03, 2020 2:09 pm

Can someone explainhow to do 6M.5 part b. The solution manual just says not spontaneous, but I got a value for a spontaneous reaction.

Ariel Davydov 1C
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Re: 6M.5 Part b

Postby Ariel Davydov 1C » Tue Mar 03, 2020 3:51 pm

In this reaction, Br- is oxidized and Hg2+ is reduced, resulting in a cell potential of -0.17 V, which is nonspontaneous. Hope this helps!

Caitlyn Tran 2E
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Re: 6M.5 Part b

Postby Caitlyn Tran 2E » Tue Mar 03, 2020 3:53 pm

In order to match the given equation, then bromine must be involved in the oxidation half reaction. Hence, you get 0.92 - 1.09, which is negative and indicates that the reaction is non-spontaneous.

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