6M.5 Part b

aphung1E
Posts: 101
Joined: Sat Aug 24, 2019 12:15 am

6M.5 Part b

Can someone explainhow to do 6M.5 part b. The solution manual just says not spontaneous, but I got a value for a spontaneous reaction.

Ariel Davydov 1C
Posts: 110
Joined: Thu Jul 11, 2019 12:16 am
Been upvoted: 1 time

Re: 6M.5 Part b

In this reaction, Br- is oxidized and Hg2+ is reduced, resulting in a cell potential of -0.17 V, which is nonspontaneous. Hope this helps!

Caitlyn Tran 2E
Posts: 100
Joined: Fri Aug 09, 2019 12:15 am

Re: 6M.5 Part b

In order to match the given equation, then bromine must be involved in the oxidation half reaction. Hence, you get 0.92 - 1.09, which is negative and indicates that the reaction is non-spontaneous.