6M.5 Part b
Moderators: Chem_Mod, Chem_Admin
6M.5 Part b
Can someone explainhow to do 6M.5 part b. The solution manual just says not spontaneous, but I got a value for a spontaneous reaction.
-
Ariel Davydov 1C
- Posts: 110
- Joined: Thu Jul 11, 2019 12:16 am
- Been upvoted: 1 time
Re: 6M.5 Part b
In this reaction, Br- is oxidized and Hg2+ is reduced, resulting in a cell potential of -0.17 V, which is nonspontaneous. Hope this helps!
-
Caitlyn Tran 2E
- Posts: 100
- Joined: Fri Aug 09, 2019 12:15 am
Re: 6M.5 Part b
In order to match the given equation, then bromine must be involved in the oxidation half reaction. Hence, you get 0.92 - 1.09, which is negative and indicates that the reaction is non-spontaneous.
Return to “Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams”
Who is online
Users browsing this forum: No registered users and 9 guests