The question asks to calculate Ecell for the concentration cell:
Pt(s)|H2(g, 1 bar)|H+(aq, pH=4.0)||H+(aq, pH=3.0)|H2(g, 1 bar)|Pt(s).
When calculating Ecell, I thought n = 2 because 2 electrons are transferred. Why is n = 1?
6N.7 (b)
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Charlyn Ghoubrial 2I
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Re: 6N.7 (b)
H is going from either 0 (because it’s by itself) to +1 and viseversa so only 1 electron is being transferred
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BritneyP- 2c
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Re: 6N.7 (b)
The reaction is a concentration cell which means the electron transfer has to be the same on both sides. H+ has to transfer 1 electron to lose its charge to become H2, so the moles of electron transferred would be 1
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