6.M.13 part b

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Emily Lo 1J
Posts: 50
Joined: Thu Sep 19, 2019 12:16 am

6.M.13 part b

Postby Emily Lo 1J » Thu Mar 05, 2020 2:05 pm

SO the problem is asking:
Identify the reactions with K > 1 in the following list and, for each such reaction, identify the oxidizing agent and calculate the standard cell potential.

MnO4−(aq) + 8 H+(aq) + 5 Ce3+(aq)→5 Ce4+(aq) + Mn2+(aq) + 4 H2O(l)

Both MnO4- and Ce3+ are losing electrons, does anyone know how to determine which one is the cathode and which one is the anode?

Cooper Baddley 1F
Posts: 100
Joined: Wed Sep 18, 2019 12:19 am

Re: 6.M.13 part b

Postby Cooper Baddley 1F » Thu Mar 05, 2020 3:22 pm

The Mn is actually being reduced because it is going from a charge of +7 to +2 so that would be your cathode.

Emily Lo 1J
Posts: 50
Joined: Thu Sep 19, 2019 12:16 am

Re: 6.M.13 part b

Postby Emily Lo 1J » Thu Mar 05, 2020 7:23 pm

Cooper Baddley 1F wrote:The Mn is actually being reduced because it is going from a charge of +7 to +2 so that would be your cathode.

Oh that makes more sense! Thank you!!


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