How do you get the half reaction for the anode? Shouldn't O2 and H+ be on different sides of the equation?
Re: 6L.3 part d
Posted: Fri Mar 06, 2020 3:09 pm
by Aman Sankineni 2L
I think the reason why O2 and H+ are on the same side is because the reaction would not be oxidizing if it was either H+ -> O2 or O2 -> H+ The equation has to be H2O -> O2 + H+ because then the reaction will be oxidizing for H in H2O -> H+