6M.1

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Bryce Ramirez 1J
Posts: 120
Joined: Sat Aug 24, 2019 12:16 am

6M.1

Postby Bryce Ramirez 1J » Thu Mar 05, 2020 6:19 pm

When setting up the equation for the energy of the cell, the problem gives us the cell diagram with the unknown metal on the left side and the Cu^2+ to Cu on the right side. So when setting up to solve for the unknown metal, I set it as the anode because it was on the left side and the Copper as the cathode. However, the answer says that the copper is the anode and the unknown metal as the cathode. Can someone explain why this is the right way to solve the problem?

chimerila
Posts: 53
Joined: Wed Nov 14, 2018 12:23 am
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Re: 6M.1

Postby chimerila » Thu Mar 05, 2020 9:46 pm

https://lavelle.chem.ucla.edu/forum/viewtopic.php?t=11592

I was also confused by this, since the solution manual rewrites the cell notation, but hopefully this helps!


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