Page 1 of 1

Midterm 2012 Q: 7A

Posted: Sun Feb 07, 2016 6:43 pm
by Antonio Melgoza 2K
How do you get -0.35? I got -2.02 for my answer

Re: Midterm 2012 Q: 7A

Posted: Sun Feb 07, 2016 7:23 pm
by Cesar Martinez 2A
I'm not quite understanding how you're getting -2.02 with those values. You're given Ecell=-0.689 and Eanode=0.34

The equation you will use is Ecell=Ecathode-Eanode, where you want to find the value of Ecathode.

Rearrange the equation to solve for Ecathode:

Ecathode=Ecell+Eanode

So, plugging in the numbers for Ecell and Eanode:

(Ecathode)=(-0.689v)+(0.34v)

Ecathode=-0.35

Re: Midterm 2012 Q: 7A

Posted: Sun Feb 07, 2016 7:55 pm
by Antonio Melgoza 2K
I was dividing 0.689 by 0.34, I get it now. Thanks!