How do we determine n for Gibbs Free Energy?
In 6Fe^3+ + 2Cr^3+ + 7H2O -> 6Fe^2+ + Cr2O7^2- + 14H^+ (which is problem 6L1 in the textbook) it says that n is 6. How do we get this since it isn't asking for delta n.
Finding n
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Re: Finding n
In this equation, n stands for the number of electrons transferred. To find this, write out the two half reactions and balance them. The number of electrons that are transferred in the balanced equations is n.
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Re: Finding n
Always make sure the electrons are balanced for both reactions. then the balanced electrons is the number of moles.
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Re: Finding n
in this case, n is used to represent number of moles of electrons transferred. To determine this, balance the half-reactions and look at the oxidation numbers to see how many electrons are transferred.
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Re: Finding n
n would be the number of electrons transferred after both half reactions are balanced.
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