## 14.9 and using G=-nFE

$\Delta G^{\circ} = -nFE_{cell}^{\circ}$

katherine_r
Posts: 7
Joined: Wed Sep 21, 2016 2:55 pm

### 14.9 and using G=-nFE

Calculate the standard reaction Gibbs free energy for the following cell reactions....

In the solution manual, the Faraday constant they use is 9.6485x10^4 but the constant given on our formula sheet is 96,4853. Which number is correct? Thank you!

Posts: 10
Joined: Fri Jul 22, 2016 3:00 am

### Re: 14.9 and using G=-nFE

Both of those constants are the same, just one is a little more specific. I wouldn't worry about which one you use, just use the one given when you take the test.

Nick_OConnell_2F
Posts: 10
Joined: Fri Jul 15, 2016 3:00 am

### Re: 14.9 and using G=-nFE

At first glance I was going to say they were the same also. However, the one on the formula sheet is actually incorrect. Notice how on the Formula sheet, F = 96,4853. If the three was meant to be included, it should have read 964,853. Upon looking up the actual constant, the 3 is the first decimal value when not using scientific notation. Thus, the formula sheet should say 96,485.3 C * mol^-1 or if using the value given in the text, 9.64853*10^4.

Also, if you look at the value of Faraday's constant on the quiz formula sheet, it gives the correct value of 96,485 C * mol^-1.

AllisonKimbell
Posts: 7
Joined: Tue Jun 21, 2016 3:00 am

### Re: 14.9 and using G=-nFE

Online research also clarifies that the number on the formula sheet is wrong.

Dr. Lavelle... this might be something you bring up to the people at the Course Reader store

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