Calculate the standard reaction Gibbs free energy for the following cell reactions....
In the solution manual, the Faraday constant they use is 9.6485x10^4 but the constant given on our formula sheet is 96,4853. Which number is correct? Thank you!
14.9 and using G=-nFE
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Re: 14.9 and using G=-nFE
Both of those constants are the same, just one is a little more specific. I wouldn't worry about which one you use, just use the one given when you take the test.
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Re: 14.9 and using G=-nFE
At first glance I was going to say they were the same also. However, the one on the formula sheet is actually incorrect. Notice how on the Formula sheet, F = 96,4853. If the three was meant to be included, it should have read 964,853. Upon looking up the actual constant, the 3 is the first decimal value when not using scientific notation. Thus, the formula sheet should say 96,485.3 C * mol^-1 or if using the value given in the text, 9.64853*10^4.
Also, if you look at the value of Faraday's constant on the quiz formula sheet, it gives the correct value of 96,485 C * mol^-1.
Also, if you look at the value of Faraday's constant on the quiz formula sheet, it gives the correct value of 96,485 C * mol^-1.
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Re: 14.9 and using G=-nFE
Online research also clarifies that the number on the formula sheet is wrong.
Dr. Lavelle... this might be something you bring up to the people at the Course Reader store
Dr. Lavelle... this might be something you bring up to the people at the Course Reader store
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