14.9 and using G=-nFE


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katherine_r
Posts: 7
Joined: Wed Sep 21, 2016 2:55 pm

14.9 and using G=-nFE

Postby katherine_r » Sat Feb 11, 2017 8:44 pm

Calculate the standard reaction Gibbs free energy for the following cell reactions....

In the solution manual, the Faraday constant they use is 9.6485x10^4 but the constant given on our formula sheet is 96,4853. Which number is correct? Thank you!

AlyssaD_2K
Posts: 10
Joined: Fri Jul 22, 2016 3:00 am

Re: 14.9 and using G=-nFE

Postby AlyssaD_2K » Sat Feb 11, 2017 8:52 pm

Both of those constants are the same, just one is a little more specific. I wouldn't worry about which one you use, just use the one given when you take the test.

Nick_OConnell_2F
Posts: 10
Joined: Fri Jul 15, 2016 3:00 am

Re: 14.9 and using G=-nFE

Postby Nick_OConnell_2F » Sat Feb 11, 2017 9:00 pm

At first glance I was going to say they were the same also. However, the one on the formula sheet is actually incorrect. Notice how on the Formula sheet, F = 96,4853. If the three was meant to be included, it should have read 964,853. Upon looking up the actual constant, the 3 is the first decimal value when not using scientific notation. Thus, the formula sheet should say 96,485.3 C * mol^-1 or if using the value given in the text, 9.64853*10^4.

Also, if you look at the value of Faraday's constant on the quiz formula sheet, it gives the correct value of 96,485 C * mol^-1.

AllisonKimbell
Posts: 7
Joined: Tue Jun 21, 2016 3:00 am

Re: 14.9 and using G=-nFE

Postby AllisonKimbell » Sun Feb 12, 2017 11:14 pm

Online research also clarifies that the number on the formula sheet is wrong.

Dr. Lavelle... this might be something you bring up to the people at the Course Reader store


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