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Delta G= Wmax

Posted: Fri Feb 09, 2018 3:47 pm
by Kelly Seto 2J
Can someone explain what Wmax means? Also why are delta G and Wmax equal at constant T and P? What is the relationship between the two?

Re: Delta G= Wmax

Posted: Fri Feb 09, 2018 3:52 pm
by Aditya Pimplaskar 1J
Wmax refers to the maximum amount of work a system can do. Delta G is the maximum work that a system can do at a given temperature and pressure. So we can equate the two.

I also found this previous post on Chemistry Community from Dr. Lavelle: viewtopic.php?t=5141

Re: Delta G= Wmax

Posted: Mon Feb 12, 2018 4:05 pm
by aaron tang 2K
DeltaG is the maximum amount of work a system can do at a given temperature and pressure, while WMAX is the maximum amount of work a system can do. Therefore, you can set them equal to each other.

Re: Delta G= Wmax

Posted: Thu Feb 15, 2018 9:12 am
by melissa carey 1f
Whats the relationship between free energy and max work - are they equal?

Re: Delta G= Wmax

Posted: Thu Feb 15, 2018 11:54 pm
by Julie Steklof 1A
melissa carey 1f wrote:Whats the relationship between free energy and max work - are they equal?


I wrote in my notes from 2/9 that maximum cell potential is directly related to the free energy difference between reactants and products in the cell/ redox reaction.

Re: Delta G= Wmax

Posted: Sun Feb 18, 2018 8:13 pm
by DamianW
Why are they equal?

Re: Delta G= Wmax

Posted: Sun Feb 18, 2018 9:00 pm
by Ridhi Ravichandran 1E
Wmax actually represents the maximum non-expansion work a reaction can do. Basically, an exothermic reaction will release a certain amount of energy, and this energy can be harnessed to do other kinds of work, such as power a non-spontaneous reaction.

Re: Delta G= Wmax

Posted: Sun Feb 18, 2018 9:02 pm
by Scott Chin_1E
Does Wmax usually occur when the system is at equilibrium?

Re: Delta G= Wmax

Posted: Mon Feb 19, 2018 9:39 pm
by 804899546
Scott Chin_1E wrote:Does Wmax usually occur when the system is at equilibrium?

No, at equilibrium Delta G and Ecell are equal to zero, and therefore work at equilibrium would be equal to zero. This makes sense, as at equilibrium there would be no electrons flowing between the anode and the cathode.