Problem 14.23 (b)

$\Delta G^{\circ} = -nFE_{cell}^{\circ}$

Gavin Kellerman 1D
Posts: 17
Joined: Sat Jul 09, 2016 3:00 am

Problem 14.23 (b)

For this problem, how are we figure out that Br is the anode and Hg is the cathode?

melissa carey 1f
Posts: 53
Joined: Fri Sep 29, 2017 7:06 am

Re: Problem 14.23 (b)

Br is the anode since its losing electrons, going from Br- to Br2(l). Br2(l) has an oxidation number of 0, while Br- has an oxidation number of -1. The reverse logic can be used on Hg.